1/(x+3)+1/(x^2+5x+6)=0

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Solution for 1/(x+3)+1/(x^2+5x+6)=0 equation: 



1/(x+3)+1/(x^2+5x+6)=0



Domain of the equation: (x+3)!=0

We move all terms containing x to the left, all other terms to the right

x!=-3

x∈R





Domain of the equation: (x^2+5x+6)!=0

We move all terms containing x to the left, all other terms to the right

x^2+5x!=-6

x∈R



We calculate fractions


(1*(x^2+5x+6))/((x+3)*(x^2+5x+6))+(1*(x+3))/((x+3)*(x^2+5x+6))=0



We calculate terms in parentheses: +(1*(x^2+5x+6))/((x+3)*(x^2+5x+6)), so:

1*(x^2+5x+6))/((x+3)*(x^2+5x+6)

We multiply all the terms by the denominator


1*(x^2+5x+6))

Back to the equation:

+(1*(x^2+5x+6)))





We calculate terms in parentheses: +(1*(x+3))/((x+3)*(x^2+5x+6)), so:

1*(x+3))/((x+3)*(x^2+5x+6)

We multiply all the terms by the denominator


1*(x+3))

Back to the equation:

+(1*(x+3)))





We calculate terms in parentheses: +(1*(x^2+5x+6)))+(1*(x+3))), so:

1*(x^2+5x+6)))+(1*(x+3))

We add all the numbers together, and all the variables

1*(x^2+5x+6)))+(1*(x

Back to the equation:

+(1*(x^2+5x+6)))+(1*(x)

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